2w^2-32w=0

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Solution for 2w^2-32w=0 equation: 



2w^2-32w=0

a = 2; b = -32; c = 0;
Δ = b2-4ac
Δ = -322-4·2·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$


$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-32}{2*2}=\frac{0}{4}
=0
$


$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+32}{2*2}=\frac{64}{4}
=16
$

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